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authorJosh Morman <jmorman@perspectalabs.com>2019-08-01 16:52:26 -0400
committerMartin Braun <martin.braun@ettus.com>2019-11-06 18:01:02 -0800
commita402fc432ec2019e5bfc70c3f78beef83b450f01 (patch)
tree6bacb2b14ddc2a714d7f7ddabcdb470024fc7457 /grc/core/blocks/embedded_python.py
parentabba02bd39b6f6fabb63755b4909d1d3f7d8ba4b (diff)
grc: embedded python module show_id flag
It is necessary to have access to the show_id flag for a python module in grc to be able to access it elsewhere. This adds the flag when the module object is created in the block library.
Diffstat (limited to 'grc/core/blocks/embedded_python.py')
-rw-r--r--grc/core/blocks/embedded_python.py5
1 files changed, 4 insertions, 1 deletions
diff --git a/grc/core/blocks/embedded_python.py b/grc/core/blocks/embedded_python.py
index ea9f71abad..94b40580c9 100644
--- a/grc/core/blocks/embedded_python.py
+++ b/grc/core/blocks/embedded_python.py
@@ -230,12 +230,15 @@ class EPyModule(Block):
to set parameters of other blocks in your flowgraph.
""")}
+ epy_flags=Block.flags
+ epy_flags.set(epy_flags.SHOW_ID)
+
parameters_data = build_params(
params_raw=[
dict(label='Code', id='source_code', dtype='_multiline_python_external',
default='# this module will be imported in the into your flowgraph',
hide='part')
- ], have_inputs=False, have_outputs=False, flags=Block.flags, block_id=key
+ ], have_inputs=False, have_outputs=False, flags=epy_flags, block_id=key
)
templates = MakoTemplates(