From a402fc432ec2019e5bfc70c3f78beef83b450f01 Mon Sep 17 00:00:00 2001
From: Josh Morman <jmorman@perspectalabs.com>
Date: Thu, 1 Aug 2019 16:52:26 -0400
Subject: grc: embedded python module show_id flag
It is necessary to have access to the show_id flag for a python module
in grc to be able to access it elsewhere. This adds the flag when the
module object is created in the block library.
---
grc/core/blocks/embedded_python.py | 5 ++++-
1 file changed, 4 insertions(+), 1 deletion(-)
(limited to 'grc/core/blocks/embedded_python.py')
diff --git a/grc/core/blocks/embedded_python.py b/grc/core/blocks/embedded_python.py
index ea9f71abad..94b40580c9 100644
--- a/grc/core/blocks/embedded_python.py
+++ b/grc/core/blocks/embedded_python.py
@@ -230,12 +230,15 @@ class EPyModule(Block):
to set parameters of other blocks in your flowgraph.
""")}
+ epy_flags=Block.flags
+ epy_flags.set(epy_flags.SHOW_ID)
+
parameters_data = build_params(
params_raw=[
dict(label='Code', id='source_code', dtype='_multiline_python_external',
default='# this module will be imported in the into your flowgraph',
hide='part')
- ], have_inputs=False, have_outputs=False, flags=Block.flags, block_id=key
+ ], have_inputs=False, have_outputs=False, flags=epy_flags, block_id=key
)
templates = MakoTemplates(
--
cgit v1.2.3